NEED TO BE ANSWERED QUICK! I WILL RATE VERY WELL! PLEASE SHOW ANSWER CLEARLY! Fi

ID: 2912580 • Letter: N

Question

NEED TO BE ANSWERED QUICK! I WILL RATE VERY WELL! PLEASE SHOW ANSWER CLEARLY!

Find the axis of symmetry of the parabola.

(y + 3)2 = -8(x - 1)

Find the coordinates of the vertex of the parabola.

-5x + y2 + 4y + 19 = 0

Find the coordinates of the foci of the ellipse.

x2/25 + y2/36 = 1

Find the coordinates of the vertices of the ellipse.

(x+3)2/4 + (y-1)2/25 = 1

Find the length of the major axis of the ellipse.

(x-2)2/9 + (y+1)2/16 = 1

Find the coordinates of the center of the ellipse.

4x2 + y2 - 40x + 6y + 105 = 0

(y+3)2=-8(x-1)

This is of the form (y-k)2=p(x-h)

Where axis of symmetry is y=k

SO for the given question , axis of symmetry is y=-3

Second question

-5x+y2+4y +19=0

y2+4y+4 +19= 5x+4

(y+2)2=5x+4-19

(y+2)2=5(x-3)

So vertex =(3,-2)

Third question

x2/25+y2/36=1

Here a =6, b =5

c = sqrt(36-25) = sqrt 11

Focii(h,k+-c) = (0,-sqrt11),(0,sqrt11)

Fourth question

(x+3)2/4 + (y-1)2/25 = 1

This is of the form

(x-h)2/a2 + (y-k)2/b2 = 1

Where vertex (h,k) is (-3,1)

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.