Consider the following information about travelers onvacation: 40% check work em

Question

Consider the following information about travelers onvacation: 40% check work email, 30% use a cell phone to stay connectedto work, 25%bring a laptop with them, 23% both check work e-mailand use a cell phone to stay connected, and 51% neither check workemail nor use a cell phone to stay connected nor bring a laptop. Inaddition, 88 out of every 100 who bring a laptop also check workemail, and 70 out of every 100 who use a cell phone to stayconnected also bring a laptop. question: a. what is the probability that a randomly selectedtraveler who checks work email also use a cell phone to stayconnected? b. what is the probability that someone who brings alaptop on vacation also uses a cell phone to stayconneceted? c. If the randomly selected traveler checked workemail and brought a laptop, what is the probability that he/sheuses a cell phone connected? Consider the following information about travelers onvacation: 40% check work email, 30% use a cell phone to stay connectedto work, 25%bring a laptop with them, 23% both check work e-mailand use a cell phone to stay connected, and 51% neither check workemail nor use a cell phone to stay connected nor bring a laptop. Inaddition, 88 out of every 100 who bring a laptop also check workemail, and 70 out of every 100 who use a cell phone to stayconnected also bring a laptop. question: a. what is the probability that a randomly selectedtraveler who checks work email also use a cell phone to stayconnected? b. what is the probability that someone who brings alaptop on vacation also uses a cell phone to stayconneceted? c. If the randomly selected traveler checked workemail and brought a laptop, what is the probability that he/sheuses a cell phone connected?

Explanation / Answer

a) P(email/cellphone)=P(Email and cell phone)/P(cellphone)                            = 0.23/0.30                            = 0.77. b) P(cell phone and lap top)=P(cell phone/lap top).P(laptop)                                = 0.70(0.25                                 =0.175. c) Hint: P(B)=P((AUC) and B)/P(AUC/B)

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