Let A be the event that randomly choosen American is Hispanic, andlet B be the e
ID: 2914313 • Letter: L
Question
Let A be the event that randomly choosen American is Hispanic, andlet B be the event that the person is white.Hispanic Not Hispanic
asian 0.000 0.036
black 0.003 0.121
white 0.060 0.691
others 0.062 0.027
d) Express "the person chosen is a nonhispanic white" in terms ofevents A and B. what is the probability of this event?
My question:
I still don't understand how Ihave to solve this problem. I tried the following:
P(A)= 0,875
P(B)= 0,751
P(A and B)= P(A) x P(B), so 0,875 x 0,751= 0,657
But you can't use this rule, because here P(A) and P(B) aredependent. But at school they say it was the correct answer. Idon't understand why.
Let A be the event that randomly choosen American is Hispanic, andlet B be the event that the person is white. Let A be the event that randomly choosen American is Hispanic, andlet B be the event that the person is white.
Hispanic Not Hispanic
asian 0.000 0.036
black 0.003 0.121
white 0.060 0.691
others 0.062 0.027
d) Express "the person chosen is a nonhispanic white" in terms ofevents A and B. what is the probability of this event?
My question:
I still don't understand how Ihave to solve this problem. I tried the following:
P(A)= 0,875
P(B)= 0,751
P(A and B)= P(A) x P(B), so 0,875 x 0,751= 0,657
But you can't use this rule, because here P(A) and P(B) aredependent. But at school they say it was the correct answer. Idon't understand why.
Explanation / Answer
The person chosen is a nonhispanic white" in terms of events Aand B That is non-Hispanic is Ac (A compliment) and B(white) ==>P(Ac and B) = P(B) P( Ac|B) So P(A) = 0.125 and P(B) = 0.751 Now P(Ac ) = 1- P(A) = 1-0.125 = 0.875 Required probability = 0.875 *(0.691/0.875)= 0.691 What you did is correct. What you did is correct.Related Questions
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