In an investigation into 3 different treatments, 8 individualswere selected. In

Question

In an investigation into 3 different treatments, 8 individualswere selected. In a random manner, 3 were selected from the 8 fortreatment #1, 2 were selected at random from thre remaining 5 fortreatment #2, and the remaining were given treatment #3. In howmany ways can this be done? 8*7*6*5*4*3*2*1? Thanks for the response, Gort, but I want another opiniontoo. In an investigation into 3 different treatments, 8 individualswere selected. In a random manner, 3 were selected from the 8 fortreatment #1, 2 were selected at random from thre remaining 5 fortreatment #2, and the remaining were given treatment #3. In howmany ways can this be done? 8*7*6*5*4*3*2*1? Thanks for the response, Gort, but I want another opiniontoo.

Explanation / Answer

I think this question involves combination, not permutation. Socombination formula should be applied: 8C3 x 5C2 x3C3 = 560 Hope this helps!

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