The wildlife department has been feeding a special food torainbow trout fingerli

Question

The wildlife department has been feeding a special food torainbow trout fingerlings in a pond. A Sample of the weightsof 40 trout revealed that the mean weight is 402.7 grams and thestandard deviation 8.8 grams. What is the probability thatthe mean weight for a sample of 40 trout exceeds 405.5grams? A. 0.3783 B. 0.0228 C. 1.0 D. 0.5 Which of the above is the correct answer The wildlife department has been feeding a special food torainbow trout fingerlings in a pond. A Sample of the weightsof 40 trout revealed that the mean weight is 402.7 grams and thestandard deviation 8.8 grams. What is the probability thatthe mean weight for a sample of 40 trout exceeds 405.5grams? A. 0.3783 B. 0.0228 C. 1.0 D. 0.5 Which of the above is the correct answer

Explanation / Answer

Let X be the weight of the sample X~Normal (402.7, 8.82) z = (405.5 - 402.7)/8.8 = 0.318 P(X >405.5) = P(Z > 0.318) By using a normal probability table, it was found that P(X >405.5) = P(Z > 0.318) = 0.38 Thus, (A) is the answer Hope this helps!

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