Values of x ofX P(X=x) -5 ? 1 ? 4 0.16 5 0.24 6 0.11 P(X= -5) + P(X=1) + 0.16+0.
ID: 2914972 • Letter: V
Question
Values of x ofX P(X=x) -5 ? 1 ? 4 0.16 5 0.24 6 0.11 P(X= -5) + P(X=1) + 0.16+0.24+0.11 = 1 P(X= -5) + P(X=1) = 1 - 0.16 + 0.24 + 0.11 = 0.49 P(X= -5) + P(X=1) = 0.49 This is where I am stuck. Where do I go from here? Values of x ofX P(X=x) -5 ? 1 ? 4 0.16 5 0.24 6 0.11 P(X= -5) + P(X=1) + 0.16+0.24+0.11 = 1 P(X= -5) + P(X=1) = 1 - 0.16 + 0.24 + 0.11 = 0.49 P(X= -5) + P(X=1) = 0.49 This is where I am stuck. Where do I go from here?Explanation / Answer
Given that, Values of x ofX P(X=x) -5 x1 1 x2 4 0.16 5 0.24 6 0.11 P(X= -5) + P(X=1) + 0.16+0.24+0.11 = 1 P(X= -5) + P(X=1) = 1 - 0.16 - 0.24 - 0.11 =0.49 P(X= -5) + P(X=1) = 0.49 In this situvation we share that probability(0.49) to -5and1 Values of x ofX P(X=x) -5 x1 1 x2 4 0.16 5 0.24 6 0.11 P(X= -5) + P(X=1) + 0.16+0.24+0.11 = 1 P(X= -5) + P(X=1) = 1 - 0.16 - 0.24 - 0.11 =0.49 P(X= -5) + P(X=1) = 0.49 In this situvation we share that probability(0.49) to -5and1 Values of x ofX P(X=x) -5 x1 1 x2 4 0.16 5 0.24 6 0.11 P(X= -5) + P(X=1) + 0.16+0.24+0.11 = 1 P(X= -5) + P(X=1) = 1 - 0.16 - 0.24 - 0.11 =0.49 P(X= -5) + P(X=1) = 0.49 In this situvation we share that probability(0.49) to -5and1Related Questions
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