Suppose that the GPA (between 0.0 and 4.0) of 16000 undergrads aretabulated. A)
ID: 2916685 • Letter: S
Question
Suppose that the GPA (between 0.0 and 4.0) of 16000 undergrads aretabulated.A) If the average GPA is 3.1 and we are told that 9.2% have aperfect 4.0, what's the average GPA of the sub-4.0 students?
B) If instead we are told that the overall GPA is 3.1 but theaverage of the sub-4.0 students is 2.9, how many students (innumber) have 4.0s?
I'm not so sure if there's a statistical way to solve this problem,but I could only manage to use algebra to solve for part A. I got3.01 as the GPA for part A but I'm not sure if it's right.
Explanation / Answer
a) If there average is 3.1, it is as if every student has a 3.1(that would be one scenario), so the total grade points are3.1*16000 = 49600. However, 9.2% ( or .092*16000 = 1472students) have a 4.0, accounting for 5888 points. Therefore,the other 14528 students (16000-1472 = 14528 students) account forthe other 43712 points. Thus, the average for the otherstudents is 43712/14528 =3.01
b) I will do this a little differently: We can rewrite the average GPA as GPA = (GPA)(# Students)/(#Students) ---- (this may seem stupid but it will make sensesoon) GPA = (GPA)((# Students with a 4.0) + (# Studentswithout a 4.0))/(# Students) GPA = (GPA)((# Students with a 4.0) + ((# students) -(#Students with a 4.0)))/(# Students)
Total Average GPA = ((GPA of students less than 4.0)(#Students with a 4.0) + (GPA of students less than 4.0)(#Students less than a 4.0))/(# students)
GPA = 3.1 = ((2.9)(16000-x)+(4.0)(x))/(16000) where x is thenumber of students with a 4.0
Solving for x you get that about 2909 students got a 4.0
Hope that helps
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