5. • -11 points SwokATG138.2.021. DMy Notes - Ask Your Teacher Two automobiles l

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5. • -11 points SwokATG138.2.021. DMy Notes - Ask Your Teacher Two automobiles leave a city at the same time and travel along straight highways that differ in direction by 73°. If their speeds are 40 mi/hr and 50 mi/hr respectively, approximately how far apart are the cars at the end of 20 minutes? (Round your answer to the nearest whole number.) mi Need Help? Read It Watch It Talk to a Tutor 6. O 0/1 points | Previous Answers SwokATG13 8.2.023. DMy Notes + Ask Your Teacher A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 25 mi/hr. Another ship leaves the same port at 1:30 PM. and travels S20°W at 20 mi/hr. Approximately how far apart are the ships at 3:00 PM.? (Round your answer to the nearest mile.) X mi 58 Need Help? Read It Talk to a Tutor 7. + -11 points SwokATG13 8.2.025. My Notes + Ask Your Teacher A jogger runs at a constant speed of one mile every 6 minutes in the direction S24E for 23 minutes and then in the direction N16°E for the next 16 minutes. Approximate, to the nearest tenth of a mile, the straight-line distance from the endpoint to the starting point of the jogger's course. mi Need Help? | Read It Watch It Talk to a Tutor

Explanation / Answer

multiple questions posted.please post each question seperately

5)

20 minutes = (20/60) =(1/3) hour

speed of one automobile is 40 mi/hr , other one is 50mi/hr

distance travelled in 20minutes by one automobile is (40*1/3) = (40/3) mi , other one is (50*1/3)=(50/3)mi

angle between their paths = 73o

using law of cosines ,

distance between the cars at the end of 20 minutes =[(40/3)2+(50/3)2-(2*(40/3)*(50/3)*cos73o)]

distance between the cars at the end of 20 minutes =18 miles

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