Homework 75 More Tri www.webassign net/webStudent As gr rent Responses, brit ein
ID: 2920302 • Letter: H
Question
Explanation / Answer
We have given sin(2)+sin()=0 and interval [0,2pi)
using double angles formula sin(2)=2sin()cos()
sin(2)+sin()=0
2sin()cos()+sin()=0
sin()(2cos()+1)=0
sin()=0 or cos()=-1/2
=0,pi or =2pi/3,4pi/3
=0,pi,2pi/3,4pi/3
25) We have given tan(/2)-sin()=0 and interval [0,2pi)
using half angle formula tan(/2)=[1-cos()]/sin()
tan(/2)-sin()=0
[1-cos()]/sin()-sin()=0
1-cos()-sin2()=0
1-sin2()-cos()=0
plug 1-sin2()=cos2()
cos2()-cos()=0
cos()(cos()-1)=0
cos()=0 or cos()=1
=pi/2,3pi/2 or =0
=pi/2,3pi/2,0
26) We have given tan()+cot()=4sin(2) and interval [0,2pi)
tan()+cot()=4sin(2)
tan()+cot()-4sin(2)=0
sin()/cos()+cos()/sin()-4sin(2)=0
[sin2()+cos2()-4sin(2)*cos()sin()]/cos()sin()=0
[sin2()+cos2()-4sin(2)*cos()sin()]=0
plug this sin2()+cos2()=1 and cos()sin()=sin(2)/2 into above equation
[1-4sin(2)*sin(2)/2]=0
1-2sin2(2)=0
sin2(2)=1/2
sin(2)=1/sqrt(2) or sin(2)=-1/sqrt(2)
2=pi/4,3pi/4 or 2=5pi/4,7pi/4
=pi/8,3pi/8 or =5pi/8,7pi/8
=pi/8,3pi/8,5pi/8,7pi/8
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