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zillow-Yahoo Search Re- Fwd: Welcome to perix v?° Login-perfx wireline Se A ALEKS-Arosea Falcon-1 x /x/lsl.exe/1o_u-lgNslkr7)8P3jH-IBgu6plCeFuOF 7UjsroJMKrbFHXPNvwiLIE9GQOP IrZonZhtsCEAoj1PKtnig i Secure https://www-awh.aleks.com/alekscgi/x/Isl.exe/1o O TRIANGLES AND VECTORS Solving a word problem using the law of cosines Arosea v A ship leaves port A and travels 56 miles due west to point ?. It then adjusts its course 35° northward. It travels 93 miles in that direction until it reaches Port B. What angle 8 with respect to due north could the ship have used to travel directly from Port A to Port B? See the figure below. Port B 93 miles 359 56 miles Port A Carry your intermediate computations to at least four decimal places. Round your answer to the nearest tenth of a degree Check ExplanationExplanation / Answer
applying law of cosines to find the length of 3rd side
angle C = 180 - 35 = 145 degrees
AB = sqrt [ 93^2 + 56^2 - 2 * 93* 56 cos 145 ]
AB = 142.54 miles
now applying law of sines
93 / sin A = 142.54 / sin 145
sin A = 21.9767
hence , theta = 90 - 21.9767
theta = 68 degrees
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