core: 0.17 of 1 pt 10of13(10 complete) HW Score: 42.95%, 5.5 6.3.97 Question Acc
ID: 2921309 • Letter: C
Question
core: 0.17 of 1 pt 10of13(10 complete) HW Score: 42.95%, 5.5 6.3.97 Question According o a recen study he ca a ace ength for adu males o a certain species o tarantuia are normally distributed with a mean of . 18 14 mm and a standard de at on of ·1.64 mm Complete parts a trough d below here to view page 1 of the standard normal distribution table. Click here to a. Find the percentage of the tarantulas that have a carapace length between 16 mm and 17 mm. The percentage of the tarantulas that have a carapace length between 16 and 17 is 14.52 %. (Type an integer or decimal rounded to two decimal places as needed.) b. Find the percentage of the tarantuilas that have a carapace length exceeding 19 mm. The percentage of the tarantulas that have a carapace length exceeding 19 is 30.15%. Type an integer or decimal rounded to two decimal places as needed.) c. Determine and interpret the quartiles for the carapace length of these tarantulas The first quartile is Type an integer or decimal rounded to two decimal places as needed.)Explanation / Answer
a) P(16<X<17)
= P((16-18.14)/1.64<Z<(17-18.14)/1.64)
= P(-1.30488<Z<-0.69512)
= 14.75%
b) P(X>19)
= P(Z>(19-18.14)/1.64)
= 30.00%
c) First Quartile = -0.67449*1.64+18.14 = 17.03
Second Quartile = 0*1.64+18.14 = 18.14
Third Quartile = 0.67449*1.64+18.14 = 19.25
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