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Name two of simple random Sample. of groun 2. A state inspector in NJ is estimat

ID: 2921822 • Letter: N

Question

Name two of simple random Sample. of groun 2. A state inspector in NJ is estimating the mean weight of packages weight to chuck labeled "3 pounds." A sample of 36 packages reveals the mean be 3.01 pounds, with a population standard deviation of 0.03 pound. a. What is the estimated population mean b. What is the standard error of the sample mean? c. Determine a 96% confidence interval for the population mean. As a condition of employment, TKC Industries applicants must pass a drug Of the last 220 applicants, 14 failed the test a. Develop a 99% confidence interval for the proportion of applicants wo 3. the test Would it be reasonable to conclude that 10% of the applicants fail the tes Explain b. Family USA magazine surveyed 20 of its subscribers, and found the average annual health premiums is $10,979. The standard deviation $1000 a. Develop a 90% confidence interval for the population mean. b. How large a sample is needed to find the population mean within $250 at 4. of the sample was 99% confidence? The National Weight Control Registry found that 459 people lost at least 30 pound out of 2700 registrants. a. Develop a 95% confidence interval for this fraction. b. Is it possible that population percentage is 18%? c. How large a sample is needed to estimate the proportion within 0.5% with 5. 95% confidence?

Explanation / Answer

2)a)estimated mean =3.01

b) std error =std deviation/(n)1/2=0.03/(36)1/2 =0.005

c) for 96% CI ; z =/-+2.0537

therefore confidence interval =sample mean -/+ z*Std error =2.9997 ; 3.0203

3)

here p=14/220 =0.0636 ; n=220

and std error =(p(1-p)/n)1/2 =0.0165

foir 99% Ci ; z=2.5758

therefore 99% confidence interval =sample proportion -/+ z*std error =0.0212 ; 0.1060

b)as above interval contain 10% (0.1) as probable value for population proportion we can not reject the conclusion that 10% failed the test,

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