4. Suppose basketball player has a 90 percent chance of making a free throw. Sup
ID: 2921943 • Letter: 4
Question
4. Suppose basketball player has a 90 percent chance of making a free throw. Suppose the player starts shooting free throws. What is the probability that the player will MISS exactly 5 free throws before making one? What is the probability that the player will make exactly 10 free throws before missing three? 5. Suppose a nonstandard roulette wheel is created, with 36 slots, numbered 1 to 36, with each slot equally likely. (It is nonstandard in the sense that a typical wheel has two additional slots, numbered 0 and 00.) What is the mean and variance of the outcome of a spin of the wheel?Explanation / Answer
4) P(missing) = 1 - 0.9 = 0.1
P(missing 5 throws before making one) = 0.15 * 0.9 = 0.000009
P(making 10 throws before missing three) = 12C10 * 0.910 * 0.12 * 0.1 = 0.023
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.