In a particular game, a fair die is tossed. If the number of spots showing is ei

Question

In a particular game, a fair die is tossed. If the number of spots showing is either 4 or 5 you win $1; if the number of spots showing is 6 you win $4; and if the number of spots showing is 1, 2, or 3, you win nothing. If it costs you $1 to play the game, the probability that you break even is: In a particular game, a fair die is tossed. If the number of spots showing is either 4 or 5 you win $1; if the number of spots showing is 6 you win $4; and if the number of spots showing is 1, 2, or 3, you win nothing. If it costs you $1 to play the game, the probability that you break even is:

Explanation / Answer

f(1) = 0

f(2) = 0

f(3) = 0

f(4) = 1

f(5) = 1

f(6) = 4

In order to break even, one needs to earn 1.

This can only happen if the number of spots is 4 or 5.

=> Probability = 2/6 = 1/3 = 0.33.

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