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ophe Homework x+ www.webassign.net/web/Student/Assignment-Responses/submit?dep-17070050 97% Search 0686 eBook 18. 0.51 points | Previous Answers MIntroStat9 5.E.514.XP My Notes Ask Your Teacher Durabl breaking strength of untreated fabric is normally distributed with mean 52.2 pounds and standard deviation 1.8 pounds. The same type of fabric after treatment has normally distributed breaking strength with mean 24.8 pounds and standard deviation 1.8 pounds. A clothing manufacturer tests 3 specimens of each fabric. All 6 strength measurements are independent. (Round your answers to four decimal places.] Enter number. fabrics are treated to improve their recovery from wrinkles after washing. Unfortunately, the treatment also reduces the strength of the fabric. The (a) What is the probabllity that the mean breaking strength of the 3 untreated speclmens exceeds 50 pounds? 9830 (b) What is the probabllity that the mean breaklng strength of the 3 untreated speclmens is at least 25 pounds greater than the mean strength of the 3 treated specimens? eBook Submit Answer Save Progress Practice Another Version 19. 1/1 points| Previous Answers MlintroStat9 5.E.517.XP My Notes Ask Your Tea Typographic errors in a text are either nonword errors (as when "the" is typed as "teh") or word errors that result in a real but incorrect word. Spell-checking software will catch nonword errors but not word errors. Human proofreaders catch 70% of word errors. You ask a fellow student to proofread an essay in which you have deliberately made 12 word errors. What is the smallest number of misses m with P(X 2 m) no larger than 0.05? You might consider m or more misses as evidence that a proofreader actually catches fewer than 70% of word errors. misses eBook 9:20 PM lype here to search 10/3/2017 19

Explanation / Answer

Let u stand for untreated and t stand for treated.

u - t = 52.2 - 24.8 = 27.4

= sqrt(1.82/3 + 1.82/3) = 1.4697

P(u - t > 25) = P(Z >(25 - 27.4)/1.4697) = P(Z > -1.6330) = 0.9488

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