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Quiz: Chapter 6 Quiz Submit Quiz This Question: 1 pt 6 of 8 (0 complete) | This

ID: 2922260 • Letter: Q

Question

Quiz: Chapter 6 Quiz Submit Quiz This Question: 1 pt 6 of 8 (0 complete) | This Quiz: 8 pts possible The average price of a television on a certain Web site is $830. Assume the price of these televisions follows the normal distribution with a standard deviation of $180. Complete parts a through d below. a. What is the probability that a randomly selected television from the site sells for less than $700? (Round to four decimal places as needed.) b. What is the probability that a randomly selected television from the site sells for between $400 and $500? L (Round to four decimal places as needed.) c. What is the probability that a randomly selected television from the site sells for between $900 and $1,000? (Round to four decimal places as needed.) d. There are 12 televisions on the site. How many televisions are within a $800 budget? There are televisions on the site that are within a $800 budget Round down to the nearest whole number.)

Explanation / Answer

= 830 = 180

Z = (X - ) /

a. X = 700

=> Z = (700 - 830) / 180 = -0.7222

From the table, the probability is 0.2351.

b. X = 400

=> Z = (400 - 830) / 180 = -2.3889

From the table, the probability is 0.0084

X = 500

=> Z = (500 - 830) / 180 = -1.8333

From the table, the probability is 0.0334

=> P(400 < Z < 500) = 0.0334 - 0.0084 = 0.0250.

c. X = 900

=> Z = (900 - 830) / 180 = 0.3889

From the table, the probability is 0.6513

X = 1000

=> Z = (1000 - 830) / 180 = 0.9444

From the table, the probability is 0.8275

=> Z(900 < Z < 1000) = 0.8275 - 0.6513

= 0.1762.

d. X = 800

=> Z = (800 - 830) / 180 = -0.1667

From the table the probability is 0.4338

12*0.4338 = 5.2056 = 5

There are 5 televisions on the site within a $800 budget.