Spell-checking software catches \"nonword errors,\" which are strings of letters

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Spell-checking software catches "nonword errors," which are strings of letters that are not words, as when "the" is typed as "eth." When undergraduates are asked to write a 250-word essay (without spell-checking), the number X of nonword errors has the following distribution.

Included two photos of the problem. There are questions A (included one write in question), B (one write in question), and C (included two write in questions).

Verizon 2:15 PM webassign.net question parts. The number of submissions remaining for oach quostion part only changes if you submit or change the answer Chapter 4 and 5 Assignment Scoring Your last submission is used for your scoro -10 points MintroStat9 4.E.057 Spell-checking software catches "nonword errors," which are strings of letters that are not words, as when "the" is typed as "eth." When undergraduates are asked to write a 250-word essay (without spell-checking), the number X of nonword errors has the following distribution My Notes Ask Your Value of X Probability 0.10 0.27 0.27 | 0.20 0.16 (a) Sketch the probability distribution for this random variable Probability Probablity 035 0.30 0.25 0.20 0.15 0.25 0.20 0.15 0.10 0.05 0.05 Errors Errors Probability Probability 035 030 0.25 0.20 0.15 0.3 0.25 0.20 0.15 0.10 0.05 Errors Errors (b) Write the event "at least one nonword error" in terms of X. X21 What is the probability of this event? () Describe the eventXs 3 in words O no more than four nonword errors O less than three nonword errors O more than three nonword errors O no more than three nonword errors What is its probability? What is the probability that X 3? 2 10/10 points| Previous Arewers MintroStt 5.E.525 XP My Notes + Ask Your Sheila's doctor is concerned that she may suffer from gestational diabetes (high blood glucose levels during pregnancy). There is variation both in the

Explanation / Answer

1 a) Graph D is correct.

b) x > 1; Option C

Probability = 0.90

c) No more than three nonwords error; Option D

Probability = 0.84

P(X < 3) = 0.64

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