(10 pts.) The population mean for the Elementary Tenacity Test (ETT) is 150 with
ID: 2922774 • Letter: #
Question
(10 pts.) The population mean for the Elementary Tenacity Test (ETT) is 150 with x =25. Based
upon a recent study of a group of elementary school children participating in a school lunch
program, we predicted that these children’s ETT scores would be different from the general
population of scores. We obtained the following ETT scores. Use an = .05 and answer the
following set of questions. Make sure to show your work.
145 180 176 152 148 142 179
163 159 154 167 172 146 169
157 150 161 160 153 165
a. (1 pt.) Is this a one-tail or two tail test?
b. (2 pts.) What are your hypotheses?
c. (1 pt.) Compute your mean.
d. (2pts.) Compute zobt.
e. (1 pt.) What is zcrit?
f. (1 pt.) State your results in APA format.
g. (2 pts.) State your conclusion.
Explanation / Answer
(a) Two-tail test
(b) Ho: = 150 and Ha: 150
(c)
x-bar = 159.9
(d)
SE = /n = 25/20 = 5.590169944
z = (x-bar - )/SE = (159.9 - 150)/5.59016994374947 = 1.770965838
(e)
= 0.05
Lower Critical z- score = -1.96
Upper Critical z- score = 1.96
(f) p- value = 0.0766
Since 0.0766 > 0.05, we fail to reject Ho
(g) There is no sufficient evidence that the mean is different from 150.
145 180 176 152 148 142 179 163 159 154 167 172 146 169 157 150 161 160 153 165Related Questions
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