A box of 10 gloves contains two left-handed gloves and eight right-handed gloves

Question

A box of 10 gloves contains two left-handed gloves and eight right-handed gloves. Complete parts (a) through (d). a. If two gloves are randomly selected from the box without replacement, what is the probability that both gloves selected will be right-handed? P(both right-handed) = .6222 (Round to four decimal places as needed.) b. If two gloves are randomly selected from the box without replacement, what is the probability there will be one right-handed glove and one left-handed glove selected? P(1 right-handed and 1 left-handed) = .3556 (Round to four decimal places as needed.) C. If three gloves are selected with replacement, what is the probability that all three will be left-handed? P(three left-handed) = .008 (Round to four decimal places as needed.) d. If you were sampling with replacement, what would be the answers to (a) and (b)? P(both right-handed) = .64 (Round to four decimal places as needed.) P1 right-handed and 1 left-handed) = 0 (Round to four decimal places as needed.)

Explanation / Answer

d. P(1 right handed glove and 1 left handed glove)=P(1st selection left and 2nd selection right OR 1st selection right and 2nd selection left)=2/10*8/10+8/10*2/10=0.32

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