PROBLEM 3140 POINTS = 10 + 10 + 10 + 10] DEPARTMENT OF PUBLIC SAFETY ANALYSTS AR
ID: 2922894 • Letter: P
Question
PROBLEM 3140 POINTS = 10 + 10 + 10 + 10] DEPARTMENT OF PUBLIC SAFETY ANALYSTS ARE ASSESSING RISKS ON HIGHWAYS. THEY ASSUME THAT THE EXPECTED NUMBER (INTENSITY) OF CAR COLLISIONS DURING RUSH HOURS IS MEASURED AS 0.2 PER DAY. DURING A 25-DAY PERIOD, THE VARIABLE (Y) IS GOING TO BE OBTAINED AS A TOTAL NUMBER OF CAR COLLISIONS 1. DESCRIBE THE DISTRIBUTION OF Y. WHAT PARAMETER VALUE ARE YOU GOING TO USE EVALUATING PROBABILITIES OF Y VALUES? PARAMETER = 2. WHAT IS THE CHANCE TO HAVE MORE THAN 7 CAR COLLISIONS DURING THE 25-DAY PERIOD, I.E. HOW LIKELY WILL Y BE HIGHER THAN 7? P[Y > 71- 3. WHAT IS THE CHANCE OF FINDING AT LEAST 4 AND AT MOST 7 CAR COLLISIONS DURING THE 25-DAY PERIOD? 4· WHAT IS THE CHANCE OF FINDING FEWER THAN 7 AND MORE THAN 4 CAR COLLISIONS DURING THE 25-DAY PERIOD?Explanation / Answer
1. we are going to use Poisson distribution
Parameter Mean value of variable is 0.2*25 = 5
2. P(Y>7) = 0.133
3.P(4<=Y<=7) = P(Y<=7)-P(Y<=4) = 0.867-0.440 = 0.427
4.P(4<Y<7) = P(Y>4)- P(Y>7) = 0.56-0.133 =0.427
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