1) For a t-curve with n=22, use the chart to find the two t-values that divide t
ID: 2922974 • Letter: 1
Question
1) For a t-curve with n=22, use the chart to find the two t-values that divide the area under the curve into a middle 0.90 area and two outside areas of 0.05 and report these values.
2) You would use this t-value if you wanted to use the t-interval procedure to construct a ___% confidence interval for a sample size of n=22.
TABLE IV Values of ta 3.078 6.314 12.706 31.821 63.657 df 1.886 2.920 4.303 6.965 9.925 1.638 2.353 3.182 4.541 5.841 1.533 2.132 2.776 3.747 4.604 5 1.476 2.015 2.571 3.365 4.032 5 1.440 1.943 2.447 3.143 3.707 1.415 1.895 2.365 98 3.499 8 1.397 1.860 2.306 2.896 3.355 9 1.383 1.833 2.262 2.821 3.250 10 1.372 1.812 2.228 2.764 3.16910 11 1.363 1.796 2.20 2.718 3.106 TE: See the version of e IV in Appendix A dditional values oft 1.356 1.782 2.179 2.681 3.055 12 1.350 1.771 2.160 2.650 3.012 1.345 1.761 2.145 2.624 2.977 15 1.341 1.753 2.131 2.602 2947 15 16 1.337 1.746 2.120 2.583 2.921 17 1.333 1.740 2.110 2.567 2.898 18 1.330 1.734 2.10 2.552 2.87818 19 1.328 1.729 2.093 2.539 2.861 9 20 1.325 1.725 2.086 2.528 2.845 20 21 1.323 1.721 2.080 2.518 2.831 21 22 1.321 1.717 2.074 2.508 2.819 22 23 1.319 1.714 2.069 2.500 2.80723 24 1.318 1.71 2.064 2.492 2.79724 25 1.316 708 2.060 2.485 2787 25 26 1.315 1.706 2.056 2.479 2.779 26 27 1.314 1.703 2.052 2.473 2.77 27 28 1.313 .701 2.048 2.467 2.763 29 1.311 1.69 2.045 2.462 2.756 29 30 1.310 1.697 2.042 2.457 2.750 30 35 1.306 1.690 2.030 2.438 2.724 35 40 1.303 1684 2.02 2.423 2.704 40 50 1.299 1.676 2.009 2.403 2.678 50 60 1.296 1.671 2.000 2.390 2.660 60 70 1.294 1.667 1.994 2.38 2.64870 801 1.292 1.664 1.990 2.374 2.639 80 90 1.291 1.662 1.987 2.369 2.63290 100 1.290 1.660 1.984 2.364 2.626 100 1000 1.282 1.646 1962 2.330 2.581 1000 2000 1.282 1.646 1.961 2.328 2.5782000 1.282 1.645 1.960 2.326 2.576 Z0.10 Z0.0s 0.025 0.01 0.005Explanation / Answer
1. Degrees of freedom = 22 - 1 = 21
t0.05 corresponding to 21 degrees of freedom = 1.721
Hence,
The two values covering middle 90% of the area will be -1.721, 1.721
2. We would use this t value if we want to construct a 90% confidence interval for a sample size of n = 22
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