The nimber of customers areiving at the store between 10:00 to 111:00 for 6 rand

Question

The nimber of customers areiving at the store between 10:00 to 111:00 for 6 randomly seected weekdays are
15, 21, 14, 28, 16, 8
The numerical value of sample standard deviation of customers arriving at the store between 10:00 to 11:00 is equal to
approximately 2152.96
approximately 16.2182

approximately 464

approximately 6.8117
The nimber of customers areiving at the store between 10:00 to 111:00 for 6 randomly seected weekdays are
15, 21, 14, 28, 16, 8
The numerical value of sample standard deviation of customers arriving at the store between 10:00 to 11:00 is equal to
approximately 2152.96
approximately 16.2182

approximately 464

approximately 6.8117

15, 21, 14, 28, 16, 8
The numerical value of sample standard deviation of customers arriving at the store between 10:00 to 11:00 is equal to
approximately 2152.96
approximately 16.2182

approximately 464

approximately 6.8117

Explanation / Answer

Since we have been asked to calc. the sample deviation:

We first find sample mean = 17

Now, to calculate sample deviation = sqrt( (X1-Mean)^2 +.. (Xn-Mean)^2)) / n-1, where n = 6

So, Sample deviation = sqrt( (15-17) ^2 + (21-17)^2+ (14-17)^2 + (28-14)^2 + (16-14)^2 + (8-14)^2) /6-1 = 6.8117

So, answer is  approximately 6.8117

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