According to a census bureau, 12.5% of the population in a certain country chang

Question

According to a census bureau, 12.5% of the population in a certain country changed addresses from 2008 to 2009, In 2010, 15 out of a random sample of 200 citizens of this country said they changed addresses during the previous year (in 2009). Complete parts a through c below. a. Construct a 95% confidence interval to estimate the actual proportion of people who changed addresses from 2009 to 2010. and an upper limit of A 95% confidence interval to estimate the actual proportion has a lower limit of (Round to three decimal places as needed.) b. What is the margin of error for this sample? The margin of error is Round to three decimal places as needed.)

Explanation / Answer

The statistical software output for this problem is:

One sample proportion summary confidence interval:
p : Proportion of successes
Method: Standard-Wald

95% confidence interval results:

Hence,

a) 95% confidence interval:

Lower limit = 0.038

Upper limit = 0.112

b) Margin of error = (Upper limit - Lower limit)/2 = (0.112 - 0.038)/2 = 0.037

Proportion Count Total Sample Prop. Std. Err. L. Limit U. Limit p 15 200 0.075 0.018624581 0.038496493 0.11150351

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