Assume now that the random variable X=Arrival Time is exactly normally distribut

Question

Assume now that the random variable X=Arrival Time is exactly normally distributed with mean m= -2.5 and standard deviation s= 23. Compute the probability of a flight arriving late based on this new info. I am specifically looking for numerical value of X that I can plug into template so I can get the probabilty. What would be the equation for this problem? Please provide answer too so I can compare it the answer that I come up with. Thanks

Assume now that the random variable X=Arrival Time is exactly normally distributed with mean m= -2.5 and standard deviation s= 23. Compute the probability of a flight arriving late based on this new info. I am specifically looking for numerical value of X that I can plug into template so I can get the probabilty. What would be the equation for this problem? Please provide answer too so I can compare it the answer that I come up with. Thanks

Assume now that the random variable X=Arrival Time is exactly normally distributed with mean m= -2.5 and standard deviation s= 23. Compute the probability of a flight arriving late based on this new info. I am specifically looking for numerical value of X that I can plug into template so I can get the probabilty. What would be the equation for this problem? Please provide answer too so I can compare it the answer that I come up with. Thanks

Assume now that the random variable X=Arrival Time is exactly normally distributed with mean m= -2.5 and standard deviation s= 23. Compute the probability of a flight arriving late based on this new info. I am specifically looking for numerical value of X that I can plug into template so I can get the probabilty. What would be the equation for this problem? Please provide answer too so I can compare it the answer that I come up with. Thanks

Explanation / Answer

givn mean = -2.5 and sd = 23

we know that

Z = (X-Mean)/SD

so the value for the flight to be late is 0.1 (minimum). As on an average the arriving time is -2.5 , which means that the flights are arriving early

Z = (0.1 -(-2.5))/23 = 0.113

so now we check the probability as

P ( Z>0.113 )=1?P ( Z<0.113 )=1?0.5438=0.4562

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