6 100 t 1111 59% 10:56 32 2017su-biostats-exam1A.pdf Consider the following set

Question

6 100 t 1111 59% 10:56 32 2017su-biostats-exam1A.pdf Consider the following set of snakes 25 milk snakes 40 cobras 20 rattlesnakes pythons (Note: cobras and rattlesnakes are venomous, milk snakes and pythons are non-venomous) p(V) = p(3 V) = p(3 V) = (a) What is the probability of choosing a random snake and it is venomous? (b) What is the probability that you choose three snakes (with replacement) and all are venomous? (c) What is the probability that you choose three snakes (without replacement) and all are venomous? (d) What is the probability that if you choose 7 random snakes (with replacement) you will get 4 venomous and 3 non- venomous snakes?

Explanation / Answer

p(venomous snakes)=(40+20)/(40+20+25+10)=0.6316

p(non-venomous snakes)=(25+10)/(40+20+25+10) =0.3684

Thus, we need to first chose 4 out of 7 snakes that are Venomous P(4V, 3NV)=P(V)^4*P(NV)^3 =7C3*(0.6316)^4 *(0.3684)^3= 0.278

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