a) Suppose that 83% of shelf depths of slugs produced on a CNC lathe are within
ID: 2926206 • Letter: A
Question
a) Suppose that 83% of shelf depths of slugs produced on a CNC lathe are within engineering specifications. Randomly select 13 such slugs. Find the probability that at most two of the 13 slugs has a shelf depth out of engineering specifications. b) Again using the above information (in Question 6), find the probability that at least two of the slugs has a shelf depth out of engineering specifications. a) Suppose that 83% of shelf depths of slugs produced on a CNC lathe are within engineering specifications. Randomly select 13 such slugs. Find the probability that at most two of the 13 slugs has a shelf depth out of engineering specifications. b) Again using the above information (in Question 6), find the probability that at least two of the slugs has a shelf depth out of engineering specifications. b) Again using the above information (in Question 6), find the probability that at least two of the slugs has a shelf depth out of engineering specifications. a) Suppose that 83% of shelf depths of slugs produced on a CNC lathe are within engineering specifications. Randomly select 13 such slugs. Find the probability that at most two of the 13 slugs has a shelf depth out of engineering specifications. b) Again using the above information (in Question 6), find the probability that at least two of the slugs has a shelf depth out of engineering specifications.Explanation / Answer
Probability that a slug depth is within specifications = 0.83
a) Probability that all 13 slugs are within specifications = 0.8313 = 0.0887.
Probability that only one slug is out of specifications = 13 * 0.17 * 0.8312 = 0.2362.
Probability that only two slugs are out of specifications = 13C2 * 0.172 * 0.8311 = 0.2903.
=> Probability that atmost two slugs are out of specifications = 0.0887 + 0.2362 + 0.2903 = 0.6152.
b) Probability that atleast two slugs are out of specifications = 1 - 0.0887 - 0.2362 = 0.6751.
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