The answer is not .331 or .449 or .332 The probability that a random smoker will

Question

The answer is not .331 or .449 or .332

The probability that a random smoker will develop a sever lung condition during his or her lifetime is 0.3. We will choose a random sample of 110 smokers and let X be the number of these smokers that will develop a severe lung condition. a) In our sample, find the mean and standard deviation of the number of smokers that will develop a sever lung condition. Give your answers to two decimal places. Hx-33 0x = 4.8 b) Use the normal approximation to find P(35 X 45). (Do NOT use the continuity correction.) Give your answer to three decimal places P(35 s X s 45)331 c) Use Excel ® or other software to find the exact value of P(35 45). Give your answer to three decimal places. P(35 X 45) .332

Explanation / Answer

(c) Ans :  0.367 (using Excel)   

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