In a survey of a group of men, the heights in the 20-29 age group were normally

Question

In a survey of a group of men, the heights in the 20-29 age group were normally distrbuted, with a mean of 69.5 inches and a standard deviation of 3.0 inches. A Complete parts (a) through (d) below (a) Find the probability that a study participant has a height that is less than 68 inches The probability that the study participant selected at random is less than 68 inches tall is 0.3085 (b) Find the probability that a study participant has a height that is between 68 and 71 inches The probability that the study participant selected at random is between 68 and 71 inches tail is (c) Find the probability that a study participant has a height that is more than 71 inches study parscipant is randomly selected (Round to four decimal places as needed,) Round to tour decimal places as needed.) Click to select your answer(s) 10/14/201

Explanation / Answer

solution=

a) First, we find the z-score, z = 6869.5/ 3 = 0.5, then use this look up the probability in the table and see that the answer is 0.3085

b)We already calculated the z-score for 68, z = 0.5. The z-score for 71 is z = 7169.5/ 3 = 0.5 Looking these up on the table, we get the probabilities 0.6915 and 0.3085. Since we are asked about being between two heights, we subtract those probabilities to get 0.6915 0.3085 = 0.3830

c)  Find the probability that his height is more than 71 inches.
P{X>71} => Z>0.5=> 1–0.6915= 0.3085

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