answer and explain please Given a normal population with a mean of 4.4 and stand

Question

answer and explain please

Given a normal population with a mean of 4.4 and standard deviation of 1.2 years. A random sample of 7 is obtained. (a)-The mean of the sampling distribution of the sample mean is 4.4 (b). The standard error of the sampling distribution of the sample mean is 4536 (c). Use the standard normal tables to find the fifth percentile of the standard normal distribution (d 5% of the time the sample mean will be less than what value? Round your answer to two dec na places n ise Round your answer to four decimal places. Use the closest z value. our an wens rom parts a to

Explanation / Answer

Answer to the question is as follows:

a. Mean = Mean of population = 4.4
b. Std error = sigma/sqrt(n) = 1.2/sqrt(7) = .4536
c. The 5th percentile of standard normal dist will be -1.645 from mean. So, value is 4.4-1.645*1.2 = 2.4260
d. 5% of time sample mean will be less than : 4.4 - .4536*1.943 , 1.943 is t value for df = n-1= 6, at alpha = .05, single tail
So, 3.52 is the answer

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