Suppose-year olds in a certain country average 3 hours a day unsupervised and th

Question

Suppose-year olds in a certain country average 3 hours a day unsupervised and that most of the unsupervised children live in rural areas, considered safe. Suppose that the standard deviation is 1.8 hours and the amount of time spent alone is normally distributed. We randomly survey one 4-year-old living in a rural area. We are interested in the amount of time the child spends alone per day Part (a) D Part (b) G Part (c) D Part (d) Part (e) 90% of the children spend at least how long per day unsupersed? (Round your answer to two decinal places) 5.3068 × hours Additional Materials Section 6.1

Explanation / Answer

z - score corresponding to 90% area i.e. 0.90 area to its left = 1.28

Hence,

Number of hours 90% of children spend unsupervised = 3 + 1.28*1.8 = 5.30 hours

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