ulls 3. 1, 5.3 ore: 0.5 of 1 pt 4 of 10 (10 complete) HW Sc 5.3.28-T ind a value

Question

ulls 3. 1, 5.3 ore: 0.5 of 1 pt 4 of 10 (10 complete) HW Sc 5.3.28-T ind a value of the standard normal random variable z, call it zo. such that the following probabilities are satisfied. a. P(zszo) 0.0817 e.P(-zo zs 0) = 0.3402 f. P(-2 zzo)-0.9680 g, P(zszo) = 0.5 h. P(25 zo ) = 0.0048 b. P(-Zo Szszo)-0.99 dPl-zo5 z zo) = 0.8474 c.zo 1.96 (Round to two decimal places as needed.) d. zo 1.43 (Round to two decimal places as needed.) e·h" (Round to two decimal places as needed.) Enter your answer in the answer box and then click Check Answer 3 Clear All remaining rch

Explanation / Answer

E) P(-z0 < Z < 0) = 0.3402

Or, P(Z < 0) - P(Z < -z0) = 0.3402

Or, 0.5 - P(Z < -z0) = 0.3402

Or, P(Z < -z0) = 0.1598

Or, z0 = 1.00

F) P(-2 < Z < z0) = 0.9680

Or, P(Z < z0) - P(Z < - 2) = 0.9680

Or, P(Z < z0) - 0.0228 = 0.9680

Or, P(Z < z0) = 0.9908

Or, z0 = 2.36

H) P(Z < z0) = 0.0048

Or, z0 = - 2.59

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