Question 1 A 1992 article in the Journal of the American Medical Association (\"

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Question 1 A 1992 article in the Journal of the American Medical Association ("A Critical Appraisal of 98.6 Degrees F, the Upper Limit of the Normal Body temperature, and Other Legacies of Carl Reinhold August Wundrlich") reported body temperature, gender, and heart rate for a number of subjects. The temperatures for 25 female subjects follow: 97.6 97.2 97.4 97.6 97.8 97.9 98.0 98.0 98.4 98.1 98.2 98.3 98.3 98.4 98.4 98.4 98.5 98.6 98.6 98.7 98.8 98.8 98.9 98.9 99.0 Test the hypothesis Ho: = 986 versus H 1: 986, using = 0.05. Round your answers to three decimal places (e.g. 98.765). (a) Calculate the sample mean and standard deviation. (b) Determine the test statistic to. (c) Draw conclusion. Ho- 0. Do not reject Reject Statistical Tables and Charts

Explanation / Answer

Mean = summation of all values/Number of sample data = 2456.8/25 = 98.272

Standard deviation = squared deviation/N-1 = 5.7504/24 = 0.2396

Test statistic, t = (x - mean)/(s/sqrt(n)) = (98.272 - 98.6)/(0.2396/sqrt(25)) = -0.328/0.04792 = -6.845

Reject H0

Data Deviation From Mean Deviation squared 97.6 -0.672 0.451584 97.2 -1.072 1.149184 97.4 -0.872 0.760384 97.6 -0.672 0.451584 97.8 -0.472 0.222784 97.9 -0.372 0.138384 98 -0.272 0.073984 98 -0.272 0.073984 98.4 0.128 0.016384 98.1 -0.172 0.029584 98.2 -0.072 0.005184 98.3 0.028 0.000784 98.3 0.028 0.000784 98.4 0.128 0.016384 98.4 0.128 0.016384 98.4 0.128 0.016384 98.5 0.228 0.051984 98.6 0.328 0.107584 98.6 0.328 0.107584 98.7 0.428 0.183184 98.8 0.528 0.278784 98.8 0.528 0.278784 98.9 0.628 0.394384 98.9 0.628 0.394384 99 0.728 0.529984 Total 2456.8 5.7504 Mean 98.272

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