This Question: 1 pt 80f 10 (7 complete) This Quiz: 10 pts poss A department o ed

Question

This Question: 1 pt 80f 10 (7 complete) This Quiz: 10 pts poss A department o education reported that in 2007 65% o students enroled in college or a trade school within 12 months o graduating fr high school 2013, a random sample of 320 individuals who graduated from high school 12 months prior was selected. From this sample, 236 students were found to be enrolled in college or a trade school. Complete parts a through c below. a. Construct a 90% confidence interval to estimate the actual proportion of students enrolled in college or a trade school within 12 months of graduating from high school in 2013. A 90% confidence interval to estimate the actual proportin has a lower limit of and an upper limit of (Round to three decimal places as needed.) b. What is the margin of error for this sample? The margin of error is (Round to three decimal places as needed.) e. Based on this sample, is there any evidence that this proportion has changed since 2007? Because the confidence interval found in part a | the reported proportion from 2007, this sample | evidence that this proportion has changed since then.

Explanation / Answer

here sample proportion phat=236/320=0.7375

n=320

std error =(phat*(1-phat)/n)1/2 =0.0246

for 90% CI =1.6449

hence 90% confidence interval =phat -/+ z*std error =0.697 to 0.778

b) margin of error =z*std error =0.040

c)beacuse the confidence interval found in part a exceeds the reported proportion ; this sample provide sufficient evidence that the this proportion ,.........

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