If you pay more in tuition to go to a top business school, will it necessarly re

Question

If you pay more in tuition to go to a top business school, will it necessarly result in a higher probability of a job offer at graduation? Letivethe null and alternative hypotheses for testing whether there exists a positive linear relationship between y andx? ys percentage of graduates with job omers and x-tuition cost then fit the simple linear model, E(y)-Ag + 1 x-to the data below, ls there sufficient evidence (at -0.10) of a positive inear relationship between y and x? wth 98 98 39,757 37.943 97 Find the test stat stic. 89 (Round to two decimal places as needed.) Find the p-value. p-valueE (Round to four decimal places as needed.) Make the appropriate conclusion at =0.10. Choose the correct answer below. OA Reject Ho. There is sufficient evidence that there exists a positive linear relationship between y andx. OB. Reject Ho.There is insufficient evidence that there ex sts a positive linear relationship between y and x. O C. Do not reject HoThere is insufficient evidence that there exists a positive linear relationship between y and x. D. Do not reject Ho There is sufficient evidence that there exists a positive inear relatonship between y and x.

Explanation / Answer

The statistical software output for this problem is:

Simple linear regression results:
Dependent Variable: % with Job Offer
Independent Variable: Annual Tuition ($)
% with Job Offer = 75.948088 + 0.00039074948 Annual Tuition ($)
Sample size: 10
R (correlation coefficient) = 0.0880157
R-sq = 0.0077467635
Estimate of error standard deviation: 5.7965658

Parameter estimates:

Analysis of variance table for regression model:

Hence,

Null and Alternative Hypotheses: Option A is correct.

t = 0.25

p - value = 0.4045

Since p - value is greater than 0.05, we do not reject Ho. Hence, Option C is correct.

Parameter Estimate Std. Err. Alternative DF T-Stat P-value Intercept 75.948088 59.855848 0 8 1.2688499 0.2402 Slope 0.00039074948 0.0015635239 > 0 8 0.2499159 0.4045

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