StatCrunch XLS GP S Data analys X / % Hw9 C www.webassign.net/web Student Assign

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StatCrunch XLS GP S Data analys X / % Hw9 C www.webassign.net/web Student Assignment Response sub nit?dep-16424760 psMy UNG Lognl Top Ha-Tuming pert login *elC at UGA %Wet As gn Che Draw Login Connect D Ren tPayment "StatCrunch TutorTrac Login Dode The average yearly rainfal in the Sahara desert used to be 10 inches. A climatelogist believes that amount has changed. Which represent the null and aternative hypothesis? 10 The cimatolegist takes a sample of 20 recenst yearly rainfal records and obtains an average of 10.3 inches. Suppose the data are unimodal and approximately symmetric, with no outliers, and t 1.397 Find the sample statibtic for the current average yearly rainfal sample statite-fo"v The degrees of freedom are degrees of freedom- Find the p-value c2 decenal places) uhole number) x(3 decimal places) mat is our decaer, alpha·o.oe> Fal to reject the nul hypothell. There ig ins mcient evdence that the average yearly raidal has changed. Resect the null hypothesis. There·sdoent evidence that the rverage roarly rental has changed. Raject the ~u hypothesis. There·nsuecent evidence that th-average yearly ranfal has changed. 0 Pail to reject the null hypothess.Thare is svfcent evidence that the average yearly rainfall has changed. completa the felgung sentence The cenfidenca interval cornesponding to this test would be X % confidence interval, the ine concluson by eamining a ceredence narval to determn·whether or not the na hypothesi ield b, resnet. what number vould m, look for ethn th·conficeet mervas suppos* v. eid·nght taled tert nrtead of this one, × what void th. nas, pavalve be? (3 decimal places) Type here to search

Explanation / Answer

Since the test is two tailed t test, with df = n-1 = 20-1=19, and t is 1.597

P - value is

P(t>|1.597) = 2P(t>1.597) = 0.1268

So p-value you entered is correct.

The confidence interval for the test will be 100-12.68 = 87.32%

We have to look for the population mean i.e 10 lies in the interval or not. If population mean lies in the confidence interval, then do not reject H0. Otherwise Reject H0

If we do a right tailed test, the p - value is

P(t>1.597) = 0.127/2 = 0.0635

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