The process standard deviation is 0.1, and the process control is set at plus or

Question

The process standard deviation is 0.1, and the process control is set at plus or minus 2.25 standard deviations. Units with weights less than 8.775 or greater than 9.225 ounces will be classified as defects. What is the probability of a defect (to 4 decimals)?


In a production run of 1000 parts, how many defects would be found (to 0 decimals)?

Through process design improvements, the process standard deviation can be reduced to 0.09. Assume the process control remains the same, with weights less than 8.775 or greater than 9.225 ounces being classified as defects. What is the probability of a defect (rounded to 4 decimals; getting the exact answer, although not necessary, will require Excel)?


In a production run of 1000 parts, how many defects would be found (to 0 decimals)?

What is the advantage of reducing process variation?
- Select your answer -It can substantially reduce the number of defectsIt may slightly reduce the number of defectsIt has no effect on the number of defectsItem 5

Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production process. Assume a production process produces items with a mean weight of 9 ounces.

The process standard deviation is 0.1, and the process control is set at plus or minus 2.25 standard deviations. Units with weights less than 8.775 or greater than 9.225 ounces will be classified as defects. What is the probability of a defect (to 4 decimals)?


In a production run of 1000 parts, how many defects would be found (to 0 decimals)?

Through process design improvements, the process standard deviation can be reduced to 0.09. Assume the process control remains the same, with weights less than 8.775 or greater than 9.225 ounces being classified as defects. What is the probability of a defect (rounded to 4 decimals; getting the exact answer, although not necessary, will require Excel)?


In a production run of 1000 parts, how many defects would be found (to 0 decimals)?

What is the advantage of reducing process variation?
- Select your answer -It can substantially reduce the number of defectsIt may slightly reduce the number of defectsIt has no effect on the number of defectsItem 5

Explanation / Answer

1)probability of a defect =1-P( of no defect) =1-P(-2.25<Z<2.25) =1-(0.9878-0.0122)=0.0244

expected defects =1000*0.0244 = 2.44 ~ 2 defects

2) for process improvement probability of a defect =1-P( of no defect) = 1-P(-0.225/0.09<Z<0.225/0.09)

=1-P(-2.5<Z<2.5)=1-(0.9938-0.0062)=0.0124

expected defects =1000*0.0124 = 1.24 ~ 1 defects

It can substantially reduce the number of defects

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