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For the following transformation T either give its standard matrix (i.e. the mat

ID: 2938726 • Letter: F

Question

For the following transformation T either
  • give its standard matrix (i.e. the matrix relative to thestandard bases of the domain of T and the codomain of T), if T islinear, or

T æ
ç
ç
ç
è é
ê
ê
ê
ë x y z ù
ú
ú
ú
û ö
÷
÷
÷
ø = é
ê
ê
ê
ë z-5 -x+4 y+4 z 2 x+2 y+5 z ù
ú
ú
ú
û Enter your answer as follows. Take care to read theseinstructions; the usual type/syntax checking is not possible with"matrix" entries. So type/syntax errors will attractpenalties.
  • If T is linear enter the entries ofits standard matrix starting at the cell in the top lefthandcorner, and leave any cells you don't needempty.
  • Similarly, to enter a counter-example of L2enter a scalar k and three vectors
    k   v    T(kv)     k T(v) in that order in the 4 cells of the top row of thetable, leaving all other cells empty. To be acounter-example of L2, you musthave
    T(k v) ¹ k T(v) Shorthand notation for vectors.   Usethe following shorthand to enter your vectors:
    separate the entries by commas and enclose inc( ), e.g. c(1, 2 ,3) representsthe column vector
    é
    ê
    ê
    ê
    ë 1 2 3 ù
    ú
    ú
    ú
    û

Answer: Enter your answer as follows. Take care to read theseinstructions; the usual type/syntax checking is not possible with"matrix" entries. So type/syntax errors will attractpenalties.
  • If T is linear enter the entries ofits standard matrix starting at the cell in the top lefthandcorner, and leave any cells you don't needempty.
  • Similarly, to enter a counter-example of L2enter a scalar k and three vectors
    k   v    T(kv)     k T(v) in that order in the 4 cells of the top row of thetable, leaving all other cells empty. To be acounter-example of L2, you musthave
    T(k v) ¹ k T(v) Shorthand notation for vectors.   Usethe following shorthand to enter your vectors:
    separate the entries by commas and enclose inc( ), e.g. c(1, 2 ,3) representsthe column vector
    é
    ê
    ê
    ê
    ë 1 2 3 ù
    ú
    ú
    ú
    û
T æ
ç
ç
ç
è é
ê
ê
ê
ë x y z ù
ú
ú
ú
û ö
÷
÷
÷
ø = é
ê
ê
ê
ë z-5 -x+4 y+4 z 2 x+2 y+5 z ù
ú
ú
ú
û

Explanation / Answer

one of the components of the range vector is z-5. 5 is of degree 0 . that means it is not linear. one of the components of the range vector is not linear. that means T is not a linear transformation. so, no question of finding the matrix. T æ
ç
ç
ç
è é
ê
ê
ê
ë x y z ù
ú
ú
ú
û ö
÷
÷
÷
ø = é
ê
ê
ê
ë z-5 -x+4 y+4 z 2 x+2 y+5 z ù
ú
ú
ú
û
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