QUESTION 7 A tudy was conducted determine an expectant mother\'s cgarete smoking

Question

QUESTION 7 A tudy was conducted determine an expectant mother's cgarete smoking has an ofect on ban mineta coart of her otheraise heathy baby A sample ef 77 newboms whose mothers smoked have a mean bone mineral content el 2xar smokers- 0.099 gmlem with a standard deviation of 0 026 gmiem Asarple of ?61 newborns whose mothers dd not smoke have a mean bone mineral oontent of Xbar ronsmokers- 091 gnom with a standand deviation of 0.025 gm Assume thal the variance of the underlying populations are equal State your null hypothesis Ou smokers /e u nonsmokers O u smokers u non smokers none of the above QUESTION 8 5 points Save Answer State your aternative hypothesis O u smokers a/e u nonsmokers O u smokers u non smokers none of the above QUESTION 9 5 points Save Aw Calculale he pooled standard deviation for the two groups QUESTION 10 the Standad Emor QUESTION 11 5 points Save Aw Calculate the t value for lhe difference between th?? means QUESTION 12 What is the artical value of t you will need to exceed for aipha 0057 QUESTION 13 5 points Save Amwer Based onthe above oes? based on alpha 0.06) 0?the most appropnate concluson tor your hypothesis test tgive that your tatshtal sg.tance is O You accept the nul hypothesis You fejed the alternative hypothesis. O You reject the null hypothesis and accept the atemative hypothess O You accept the nul hypothesis and fejed the aternative hypothess

Explanation / Answer

Question 7:

Let ?1?= mother who smoked and

?2? = mother who did not smoked.

The following null hypotheses need to be tested:

Ho: ?smoker? = ?nonsmoker?

Question 8:

The following alternative hypotheses need to be tested:

Ha: ?smoker? ? ? ?nonsmoker?

Question 9:

Pooled standard deviation for two groups:

???? 2 = (??1 ? 1)????12 + (??2 ? 1)????22 / (??1 + ??2 ? 2)

???? 2 =(77?1)(0.026)2+(161?1)(0.025)2 / (77+161?2)

?=0.0006

Hence ???? = 0.025

Question 10:

Calculate standard error

standard error = ???? * sqrt [ ( 1/ ??1) + (1 /??2)]

= 0.025* sqrt [ ( 1/ 77) + (1 /161)]

=0.003464

Question 11:

What is t value

t= (0.099-0.091) / 0.003464

=2.28

Question 12:

Calculate the critical value of t at alpha =0.05

critical value of t at alpha =0.05 is 1.97

Question 13:

Since it is observed that ?t?=2.28>tc?=1.97, it is then concluded that the null hypothesis is rejected and accpet the alternative hypothesis.

The data presented show that the population mean bone content in infants whose mothers smoked during pregnancy is not statistically significantly different from the population mean bone content in infants whose mothers did not smoke during pregnancy.

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