Word Online Modo de accesibilidad lector nmerswo … selected at random were given
ID: 2945786 • Letter: W
Question
Word Online Modo de accesibilidad lector nmerswo … selected at random were given either a stimulant, a tranquilizer, or an identically appearing placebo. After receiving the medication, the participants were given a battery of coordination and reaction time tests and the number of "mistakes" for each was recorded. The following table gives total number of mistakes for the entire battery of tests for the three groups Test #4 CA Total Number of Mistakes 6-10 11-15 Total 0-5 10 ?? 15 15 50 150 Based on this data, can it be concluded that the proportion of mistakes is different for the three groups? (Use 0.05) Chis 17 Ka descargar Guard Freshman medical students were asked to rate a particular core course according to level of difficulty of the material presented in lectures. The following table shows this response cross- tabulated with grade relieved in the course: 4) Dear students Perceived Difficulty of Course intermediately Very Dificult Total Please find attac Class Rank Not Difficult Final grade Upper 1/3 17 67 Lower 1/3 Obtiene demasiad CAMPOSC1@suagm.e 21 15 is there an association between Perceived difficulity of the course and class rank? (Use 0.05) DOLL Capa LockExplanation / Answer
Solution
This problem will be solved applying Chi-square Test of Independence, also known as Contingency Chi-square Test.
Now, to work out the answer,
Summary of Calculations:
Chi-square Cal =
24.8749
Chi-square Crit =
9.4877
for
? =
0.05
p-value =
5.3308E-05
Since Chi-square Cal > Chi-square Crit, null hypothesis is rejected.
So, we conclude that there is sufficient evidence to suggest that Perceived Difficulty of Course and Class Rank are associated. ANSWER
Details of Excel Calculations
CONTINGENCY
(3 x 3)
r = 3
c = 3
Oij
DF = 4
1
2
3
Oi.
1
10
40
17
67
2
20
35
12
67
3
21
15
30
66
O.j
51
90
59
200
Eij = (Oi. X O.j)/N
1
2
3
Total
1
17.085
30.15
19.765
67
2
17.085
30.15
19.765
67
3
16.83
29.7
19.47
66
Total
51
90
59
200
Chi-square = (Oij - Eij)^2/Eij
1
2
3
Total
1
2.9381
3.2178
0.3868
6.5429
2
0.4974
0.7802
3.0506
4.3281
3
1.0332
7.2758
5.6950
14.0039
Total
4.468646
11.2739
9.1324
24.8749
DONE
Chi-square Cal =
24.8749
Chi-square Crit =
9.4877
for
? =
0.05
p-value =
5.3308E-05
Since Chi-square Cal > Chi-square Crit, null hypothesis is rejected.
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