Problem 2 (Discrete Random Variable). In a game of American Roulette, a player w

Q: Problem 2 (Discrete Random Variable). In a game of American Roulette, a player w

1. There are 18 red numbers out of 38 on American Roulette. So, the probability that the outcome of a single spin will be a red number = 18/38 = 9/19 = 0.4737 2. Using Binomial distribution, probability of winning 6 out of 20 total bets is, 20C6 (9/19)6 (1 - 9/19)20-6 = 38760 * (9/19)6 * (10/19)14 = 0.0548

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Problem 2 (Discrete Random Variable). In a game of American Roulette, a player will make 20 consecutive bets on the same set of outcomes. She will place her bet on red numbers. Assume each outcomes of each spin are independent and the all outcomes of the roulette wheel are equally likely to occur 29 Figure 1: 38 Possible Outcomes. American Roulette wheel has 2 Green outcomes. 1. What is the probability that the outcome of a single spin will be a red number? 2. What is the probability of winning 6 out of the 20 total bets?

Explanation / Answer

There are 18 red numbers out of 38 on American Roulette.

So, the probability that the outcome of a single spin will be a red number = 18/38 = 9/19 = 0.4737

Using Binomial distribution, probability of winning 6 out of 20 total bets is,

20C6 (9/19)6 (1 - 9/19)20-6

= 38760 * (9/19)6 * (10/19)14

= 0.0548

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Problem 2 (Continuation) b) Consider the following E-R diagram Parts pld pName N

Problem 2 (Discrete Random Variable). In a game of American Roulette, a player w

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Problem 2 (Discrete Random Variable). In a game of American Roulette, a player w

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