In a survey of women in a certain country (ages 20 -29), the mean height was 63.

Question

In a survey of women in a certain country (ages 20 -29), the mean height was 63.4 inches with a standard deviation of 2.68 inches. Answer the following questions about the specified normal distribution. (a) What height represents the 95th percentile? (b) What height represents the first quartile? Click to view page 1 of the table. Click to view page 2 of the table (a) The height that represents the 95th percentile is inches. (Round to two decimal places as needed.) (b) The height that represents the first quartile is inches (Round to two decimal places as needed.) your answer in each of the answer boxes

Explanation / Answer

solution:-
given mean = 63.4 , standard deviation = 2.68
(a)z- score for 95th percentile is z = 1.645
x = ? + z * ?
x = 63.4 + 1.645 * 2.68
= 67.81
(b) z- score for first quartile is z = -0.6745
x = ? + z * ?
x = 63.4 + ( -0.6745) * 2.68
x = 61.59

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.