Find the p-value based on a standard normal distribution for each of the followi

Question

Find the p-value based on a standard normal distribution for each of the following standardized test statistics. (a) Z =-1.09 for a left tail test for a mean Round your answer to three decimal places. p-value= the absolute tolerance is +/-0.01 SHOW HINT LINK TO TEXT (b) Z = 4.11 for a right tail test for a proportion Round your answer to four decimal places. p-value the absolute tolerance is +/-0.01 SHOW HINT LINK TO TEXT (c) z =-1.66 for a two-tailed test for a difference in means Round your answer to four decimal places. p-value= the absolute tolerance is +/-0.01 SHOW HINT LINK TO TEXT

Explanation / Answer

Solution :

Using standard normal table,

(a) P(Z < -1.09) = 0.1379

P-value = 0.138

(b ) P(Z > 4.11) = 1 - P(Z < 4.11) = 1 - 1 = 0

P-value = 0

(c) P(Z < -1.66) = 0.0485

P-value = 2 * P(Z < -1.66) = 2 * 0.0485 = 0.0970

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.