Prob 6. Triclosan is a common ingredient in antibacterial soap products. Assume
ID: 294835 • Letter: P
Question
Prob 6. Triclosan is a common ingredient in antibacterial soap products. Assume a release occurred at a large manufacturing plant and a rapid assessment of movement rates is needed. Based on the information provided in the graph on the following page, estimate (i.e. calculate) the following for triclosan a. The distribution coefficients (Kd) in Sandy Loam b. In which material will triclosan move the fastest? Assuming an aquifer bulk density of 1.8 g/ml and a porosity of 0.25, what is the retardation factor for the Sandy Loam c. What is the most likely explanation for the difference in Kd between the different materials (sand, sandy loam, and silt loam)? d.Explanation / Answer
A) the distribution coefficient for sandy loam is calculated by the formula,
Kd = S/C
S = concentration of chemical on the sorbent (milligram per gram)
C= concentration of the test compound in solution at equilibrium ( milligram per ml)
Kd = 550/2. 1
= 261. 90 ml/gram (milligram canceled from numerator and denominator)
B) the triclosan is mostly used in polymer and it is reliable because it provides the toughnesss and strength to the polymer. Triclosan bonds with polymer chains very effectively and fastly hence it moves fast in polymer materials
C) here the retardation factor requires bulk density, porosity and distribution coefficient of sandy loam
We have formula that
R = ( 1 + ( bulk density/ porosity)( distribution coefficient))
= ( 1 + ( 1. 8/0. 25)(261. 90))
= (1+ 1885. 68)
= 1886. 68
D) the distribution coefficient is different for different material because organic carbon content is different in different material. It is observed that organic carbon content is higher for silt loam soil > sandy loam soil > sand. Hence the distribution coefficient will vary for these material
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