Question 7 (1 point) Question 7 options: A study was conducted that measured the
ID: 2948596 • Letter: Q
Question
Question 7 (1 point)
Question 7 options:
A study was conducted that measured the total brain volume (TBV) (in mm3) of patients that had schizophrenia and patients that are considered normal. Table #1 contains the TBV of the normal patients and Table #2 contains the TBV of schizophrenia patients ("SOCR data Oct2009," 2013).
Table #1: Total Brain Volume (in mm3) of Normal Patients
1663407
1583940
1299470
1535137
1431890
1578698
1453510
1650348
1288971
1366346
1326402
1503005
1474790
1317156
1441045
1463498
1650207
1523045
1441636
1432033
1420416
1480171
1360810
1410213
1574808
1502702
1203344
1319737
1688990
1292641
1512571
1635918
Table #2: Total Brain Volume (in mm3) of Schizophrenia Patients
1331777
1487886
1066075
1297327
1499983
1861991
1368378
1476891
1443775
1337827
1658258
1588132
1690182
1569413
1177002
1387893
1483763
1688950
1563593
1317885
1420249
1363859
1238979
1286638
1325525
1588573
1476254
1648209
1354054
1354649
1636119
Let ?1= mean TBV of patients that are considered normal. Let ?2 = mean TBV of patients that had schizophrenia. Compute a 90% confidence interval for the difference in TBV of normal patients and patients with Schizophrenia.
(i) For the sample from population with mean = ?1 : Determine sample mean x??1 and sample standard deviation s1
Enter sample mean to nearest integer, then comma, then sample standard deviation to nearest integer. Examples of correctly entered answers:
1332,112
-15478,3651
(ii) For the sample from the population with mean = ?2 : Determine sample mean x??2 and sample standard deviation s2{
Enter sample mean to nearest integer, then comma, then sample standard deviation to nearest integer. Examples of correctly entered answers:
1332,112
-15478,3651
(iii) Enter the level of significance ? used for this test:
Enter in decimal form. Examples of correctly entered answers: 0.01 0.02 0.05 0.10
(iv) Determine degrees of freedom df :
Enter value rounded DOWN to nearest integer.
(v) Determine t - score associated with critical value: tc
Enter in decimal form to nearest thousandth. Examples of correctly entered answers:
0.0011 0.020 0.500 0.371 2.000
(vi) Determine "error bound of the mean" E
Enter value rounded to nearest integer.
(vii) Determine confidence interval estimate of the difference ?1 – ?2:
Enter lower bound value to nearest integer, followed by < , followed by "?1-?2" for difference, followed by <, followed by upper bound value to nearest integer. No spaces between any characters. Do not use italics, but if mathematically necessary use negative signs. Examples of correctly entered answers:
0.77<?1-?2<0.78
13.12<?1-?2<13.94
-9.73<?1-?2<-8.08
(viii) Using the confidence interval, select the most correct description of the result of the survey:
A. We estimate with 90% confidence that the mean TBV of people considered normal is anywhere from 51565 mm3 more to 75677 mm3 less than the mean TBV for people with schizophrenia.
B. We estimate with 90% confidence that the true proportional TBV of people considered normal is anywhere from 51565 mm3 less to 75677 mm3 more than the mean TBV for people with schizophrenia.
C. We estimate with 90% confidence that the sample mean TBV of people considered normal is anywhere from 51565 mm3 less to 75677 mm3 more than the mean TBV for people with schizophrenia.
D. We estimate with 90% confidence that the true mean TBV of people considered normal is anywhere from 51565 mm3 less to 75677 mm3 more than the mean TBV for people with schizophrenia.
Enter letter corresponding to most correct answer
1663407
1583940
1299470
1535137
1431890
1578698
1453510
1650348
1288971
1366346
1326402
1503005
1474790
1317156
1441045
1463498
1650207
1523045
1441636
1432033
1420416
1480171
1360810
1410213
1574808
1502702
1203344
1319737
1688990
1292641
1512571
1635918
Explanation / Answer
Solution:
Part i
Here, we have to find the sample mean and sample standard deviation for the data from table 1.
Sample mean = X1bar = 1463339
Sample standard deviation = S1 = 125458
(Mean and standard deviation are calculated by using excel)
Part ii
Here, we have to find the sample mean and sample standard deviation for the data from table 2.
Sample mean = X2bar = 1451293
Sample standard deviation = S2 = 171932
(Mean and standard deviation are calculated by using excel)
Part iii
From given information, we have
Level of confidence = c = 90% = 0.90
Level of significance = ? = 1 – c = 1 – 0.90 = 0.10
Level of significance = 0.10
Part iv
Sample size of first sample = N1 = 32
Sample size of second sample = N2 = 31
Degrees of freedom = N1 + N2 – 2 = 32 + 31 – 2 = 61
Degrees of freedom = 61
Part v
We have
Degrees of freedom = 61
Level of significance = 0.10
So, by using t-table or excel, we have
Critical value = 1.670
Part vi
Error bound of the mean = E = margin of error = Interval half width
E = Critical value * sqrt[Sp2*((1/n1)+(1/n2))]
Where Sp2 is pooled variance
Sp2 = [(n1 – 1)*S1^2 + (n2 – 1)*S2^2]/(n1 + n2 – 2)
Sp2 = [(32 – 1)* 125458.2759^2 + (31 – 1)* 171932.2264^2]/(32 + 31 – 2)
Sp2 = 22536948583.7099
E = Critical value * sqrt[Sp2*((1/n1)+(1/n2))]
E = 1.670*sqrt[22536948583.7099*((1/32)+(1/31))]
E = 63188.1356
Error bound of the mean = E = 63188
Part vii
Confidence interval = (X1bar – X2bar) -/+ E
Confidence interval = (1463339.219 - 1451293.194) -/+ 63188
Confidence interval = 12046.0252 -/+ 63188
Lower limit = 12046.0252 - 63188 = -51142.1104
Upper limit = 12046.0252 + 63188 = 75234.1608
-51142.1104 < (µ1 - µ2) < 75234.1608
-51142 < (µ1 - µ2) < 75234
Part viii
From given alternatives, most correct alternative is given as below:
We estimate with 90% confidence that the true mean TBV of people considered normal is anywhere from 51565 mm^3 less to 75677 mm^3 more than the mean TBV for people with schizophrenia.
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