62&OpenVellumhMAC-4da2a8022dc57abe7dc73b87ea1; 70f19#10016 MATH 2000 Summer 2018
ID: 2949258 • Letter: 6
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62&OpenVellumhMAC-4da2a8022dc57abe7dc73b87ea1; 70f19#10016 MATH 2000 Summer 2018 Do Homework-teyinwa Doris Otj-Google Chrome k aspx?homeworkld 4888015258questionld 14&flushed; fabeäcld-50320228icenterwir ifeyinwa Doris Onijy 7/18/18 12:59 P Secure https//www.mathol MATH 2000 Summer 2018 Homework: Homework 4 Score: 0 of 1 pt 6.2.19-E 14 of 20 (18 complete) HW Score: 84 75%, 16.95 of 20 Question Hep Suppose that the siming back-to-knee length for a group of aduts has a normal distribution with a mean of 237 in and a standard deviation of a 1 2 in These deta values, use the crheria that a value x is significandly high Pix or greater)s0 0f and a value is signicantly ed are often used in the design of diferent seats Including aircraft seats, train seats, theater seats, and classroom seats Instead of using 0 05 for identilying significant low?' PO or less)s001 Frd the back-to-knee lengths separating significant values from those that are not signlicant. Using hese citeria, is a back to-knee length of 25.9 in significanty high? Find the back-to-knee lengths separating significant values from those that are not significant Back-to-knee lengths greater thanin and less than in are not signlicant and values outside that range are considered signiticent Round to one decimal place as needed) Enter your answer in the edit felos and then click check AnswerExplanation / Answer
6-2-19E
X = mean + z* sd
P(Z > z) = 0.01
z = 2.327 {normsin(0.99)}
mean = 23.7 , sd = 1.2
hence
upper limit = 23.7 + 2.327 * 1.2 = 26.4924
= 26.5
lower limit = 23.7 -2.327 *1.2 = 20.9082
= 20.9
greather than 20.9 and less than 26.5 are not significanrt
25.9 is between 20.9 and 26.5
hence not significantly high
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