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Secure https://ng.cengage.com/static/nb/ui/evo/index.htmi?elSBN-9781305586437&snapshotid-851866;&id-328342447;& (1) Stephaney Lora. D Requisite Fitness- I; Leam ngon Simpli Association for Co Go connect-Home GitHub Learn to code co IDTAP Q Search this course ste et 2 Video O Consider the experimental results for the following randomized block design. Make the calculations necessary to set up the analysis of variance table. Treatment 2 13 Blocks 3 19 15 14 19 4 21 18 Use ? " .05 to test for any significant differences. Show entries to 2 decimals, if necessary. Round p-value to four decimal places, tr your answer is zero enter "0" Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments Blocks Error Total The p-value is Select What is your conclusion? SelectExplanation / Answer
Please find Anova summary below:
ANOVA output is given below:
p-value: 7.73 * 10-5 = 0.0000773 = 0
The conclusion is there is no impact of treatment on blocks
Anova: Two-Factor Without Replication SUMMARY Count Sum Average Variance 1 3 28 9.333333 2.333333 2 3 25 8.333333 16.33333 3 3 48 16 7 4 3 58 19.33333 2.333333 5 3 24 8 1 A 5 72 14.4 29.8 B 5 55 11 27.5 C 5 56 11.2 27.7Related Questions
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