Classroom-msstate.edu xKohiberg\'s Theory of MoralAssignments xTake a Test -Anna

Question

Classroom-msstate.edu xKohiberg's Theory of MoralAssignments xTake a Test -Anna Carte CSecure https://www.mathxl.com/Student/PlayerTest.aspx?testlid-183625914&centerwinsyes; Online MAIST 2113-501 Summer 2018 Quiz: Mastery Quiz: Chapters 6-8 This Question: 1 pt 41 of 10 (0 complete) Determine the area under the standard normal arve that lies between (a) ?=-043 and ?=0.43, (D) z=-2.46 and Z-o. and (c)2.0.32 and Z-0.96. (a) The area that lies between z -0.43 and z043 is (Round to four decimal places as needed.) (b) The area that lies between z -2.48 and z Os (Round to four decimal places as needed.) (c) The area that lies between z 0.32 and z-0.98 is Round to four decimal places as needed.) Enter your answer in each of the answer boxes. 4

Explanation / Answer

Solution:-

a) P(- 0.43 < z < 0.43) = 0.332

z1 = - 0.43

z2 = 0.43

P(- 0.43 < z < 0.43) = P(z > - 0.43) - P(z > 0.43)

P(- 0.43 < z < 0.43) = 0.666 - 0.334

P(- 0.43 < z < 0.43) = 0.332

b) P(-2.46 < z < 0) = 0.493

z1 = - 2.46

z2 = 0

P(-2.46 < z < 0) = P(z > - 2.46) - P(z > 0)

P(-2.46 < z < 0) = 0.993 - 0.50

P(-2.46 < z < 0) = 0.493

c) P(0.32 < z < 0.98) = 0.21.

z1 = 0.32

z2 = 0.98

P(0.32 < z < 0.98) = P(z > 0.32) - P(z > 0.98)

P(0.32 < z < 0.98) = 0.374 - 0.164

P(0.32 < z < 0.98) = 0.21

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.