Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

number 3 and 4 An Aincraht Emergeney Lramtier (.) is adevice designed to transmi

ID: 2949753 • Letter: N

Question

number 3 and 4

An Aincraht Emergeney Lramtier (.) is adevice designed to transmit a signal in the cse of crash. The Alti Company mak isfEa.rs. the Bery Company makes 15% of them.-nd th. Calair es 80% o makes the other 5%. The E1.1's made by Alti huve a 4% fate of defects, theBery EITS harve a Company 6% rate of defects. and the Clair have a 9% rate of defect. 1. If an EL.T is randomly selected from the general population of all ELTs, then what is the probability thm it was made by the Calair Company? a randomly selected ELT is then tested and is found to be defective, what is the probability that it was made by the Calair Company? 3. Assume a total of 10,000 ELTs were manufactured. Produce a contigency table showing the number of de- fective and non defective ELT's produced by each company 4. Is there sufficient evidence to support the claim that getting a defective ELT is independent of the manufa turing company? Use a 0.05 significance level. score: _ Page 3 of 6

Explanation / Answer

The 2 x 3 contigency table is given below.

Question 4

Here

Now we will use chi-square test.

Here as we get the observed table. Now, we will observed a expected table.

Here expected values are

Expected Defects for alti = 8000 * 440/10000 = 352

Expectedved non defective for alti = 8000 * 9560/10000 = 7648

so similary, we would calculate the expected table

Now we will calculate the value of chi- square test statistic

X2 = (O - E)2/E

X2 = 15.215

Here

degree of freedom = (2-1) * (3-1) = 2

so,

X2crit. = 5.99

Here,

X2 >  X2crit.

so we will reject the null hypothesis and conclude that defective ELT is not independent of manufacturing company.

Defect AltiCompany Beri Calair Total Defective 320 90 30 440 Non-defective 7680 1410 470 9560 Total 8000 1500 500 10000