Previously, 5% o mothers smoked more than 21 cigarettes during heir pregnancy. A
ID: 2949832 • Letter: P
Question
Previously, 5% o mothers smoked more than 21 cigarettes during heir pregnancy. An obstetrician believes hat he percentage o mothers who smoke 21 cigarettes or more is less than 5% today. She random y selects 135 pregnant mothers and finds that 4 of them smoked 21 or more cigarettes during pregnancy. Test he researchers statement atthe ?-01 le e ot significance. What are the null and alternative hypotheses? Ho versus H (Type integers or decimals. Do not round.) Find the P-value P-value (Round to three decimal places as needed.) Is there sufficient evidence to support the obstetrician's statement? No, re ect the nu than 5%. A. h pothesis because he P value is less han ? There is not sufficientevidence conclude hat e percentage of mothers who smoke 2 ormore a arettes during pregnancy sess O B Yes, reject he nul h pothesis because he p value is less han ? T ere s su cer e ence o conclude that he percentage o mothers o smoke or more cigarette dun pregnancy s s than 5%. c Yes, do not reject the null hypothesis because the P-value is greater han ?. There is sufficient evidence to conclude that the percentage o mothers who smoke 21 or more ogarettes du ng pregnancy is less than 5%. D. arettes during No, do not reject the null hypothesis because the P-value is greater than ? There s not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more c pregnancy is less than 5%.Explanation / Answer
The statistical software output for this problem is:
One sample proportion summary hypothesis test:
p : Proportion of successes
H0 : p = 0.05
HA : p < 0.05
Hypothesis test results:
Hence,
Hypotheses:
Ho: p = 0.05
Ha: p < 0.05
P - value = 0.139
Conclusion: Option D is correct.
Proportion Count Total Sample Prop. Std. Err. Z-Stat P-value p 4 135 0.02962963 0.018757714 -1.0859729 0.1387Related Questions
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