a rating company stated adults between theages of 30an 35 listen to the radio an

Question

a rating company stated adults between theages of 30an 35 listen to the radio an average of 10 hrs a week.assume the variable is normally distributed and the standarddeviation is 1 hr. If 25 adults are randomly selected find thprobability that the mean number of hourss they listen to the radiowill be greater than 10.5 a rating company stated adults between theages of 30an 35 listen to the radio an average of 10 hrs a week.assume the variable is normally distributed and the standarddeviation is 1 hr. If 25 adults are randomly selected find thprobability that the mean number of hourss they listen to the radiowill be greater than 10.5

Explanation / Answer

Given X~Normal(=10, =1), n=25 The probability is P(xbar > 10.5) = P((xbar - )/(/n) > (10.5-10)/(1/sqrt(25))) = P(Z> 2.5) = 0.0062 (check normal table)

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